A. In Search of an Easy Problem题意：问你这一串数字中有没有1题解：模拟#include <bits/stdc++.h>
using namespace std;
int n,v;
int main()
{
scanf("%d",&n);
for(int i = 1;i <= n;i+...
「网络流 24 题」孤岛营救问题题解：建立分层图每一层用二进制状态表示拥有的钥匙。跑spfa就好了#include <bits/stdc++.h>
const int fx[] = {1,-1,0,0},fy[] = {0,0,1,-1},INF = 1000000;
using namespace std;
int n,m,p,k,s,ans;
int door[15][...